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0.0003x^2-0.6x+30=0
a = 0.0003; b = -0.6; c = +30;
Δ = b2-4ac
Δ = -0.62-4·0.0003·30
Δ = 0.324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.6)-\sqrt{0.324}}{2*0.0003}=\frac{0.6-\sqrt{0.324}}{0.0006} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.6)+\sqrt{0.324}}{2*0.0003}=\frac{0.6+\sqrt{0.324}}{0.0006} $
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